diff options
author | Jeff Burdges <burdges@gnunet.org> | 2018-04-25 23:07:03 +0200 |
---|---|---|
committer | Jeff Burdges <burdges@gnunet.org> | 2018-04-25 23:07:03 +0200 |
commit | 2082ab2b32a9e78a2f923d919178a8ef331cf773 (patch) | |
tree | c2edb242ef9f41d523c1065510b3a49bdc6474a1 | |
parent | 3e47fa9b5052f57e40de33272eb9b6a0f0f5f537 (diff) | |
download | papers-2082ab2b32a9e78a2f923d919178a8ef331cf773.tar.gz papers-2082ab2b32a9e78a2f923d919178a8ef331cf773.tar.bz2 papers-2082ab2b32a9e78a2f923d919178a8ef331cf773.zip |
blank lines
-rw-r--r-- | games/games.tex | 7 |
1 files changed, 0 insertions, 7 deletions
diff --git a/games/games.tex b/games/games.tex index 365013f..fef4a3a 100644 --- a/games/games.tex +++ b/games/games.tex @@ -952,13 +952,6 @@ Now $p = {1\over\kappa |X|} \sum_{C \in X} p_C$ and $b = {1\over\kappa |X|} \sum_{C \in X} b_C$ so $E({p \over b + p} | X \neq \emptyset) = {1\over\kappa}$, which yields the inequality (\dag). - - - -induction on the length of the game now still produces disjoint groupings -$\mathbb{G}$ of optimal games in which - $\sum_{\mathbb{G}} {p \over b + p} = {1\over\kappa} |\mathbb{G}|$. -We conclude that $E({p \over b + p}) = {1\over\kappa}$, as desired. \end{proof} % https://math.stackexchange.com/questions/852890/expectation-of-random-variables-ratio %%% $L - w' \over (L - w') + (w - s)$ |